Please help I’ll give you the BRAINLIEST! 1. How many moles are in 3.63 x 10^22 atoms of K?

2. How many moles are in 5.96g of BaCO3?

3. How many moles are in 1.50 grams of NH3?

4. How many liters are in 82.0g CSI?

1. Number of moles in 3.63 * 10²² atoms of K = 0.06 moles

2. Number of moles in 5.96 g of BaCO₃ = 0.03 moles

3. Number of moles of NH₃ = 0.88 moles

4. Volume of CSI = 0.50 liters

Explanation:

1. One mole of K contains 6.02 * 10²³ atoms

Number of moles in 3.63 * 10²² atoms = (3.63 * 10²² atoms/6.02 * 10²³ atoms) * 1 mole

Number of moles in 3.63 * 10²² atoms of K = 0.06 moles

2. Number of moles = mass / molar mass

Molar mass of BaCO₃ = 197.33 g/mol; mass of BaCO = 5.96 g

Number of moles = 5.96 g/ 197.33 g/mol

Number of moles in 5.96 g of BaCO₃ = 0.03 moles

3. Number of moles = mass / molar mass

Molar mass of NH₃ = 17 g/mol; mass of NH₃ = 1.50 g

Number of moles = 1.50 g/ 17 g/mol

Number of moles of NH₃ = 0.88 moles

4. Chlorosulfonyl isocyanate, ClSO2NCO, otherwise known as CSI, is a reagent used in organic synthesis. It has a density of 1.626 g/cm³.

Volume = mass/density

mass = 82.0 g; density of CSI = 1.626 g/cm³

Volume = 82.0 g / 1.626 g/cm³

Volume = 50.43 cm³

Volume = 50.43 cm³/1000 cm³ * 1 liter

Volume of CSI = 0.50 liters

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