Ammonium phosphate NH43PO4 is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid H3PO4 with liquid ammonia. Calculate the moles of ammonium phosphate produced by the reaction of 2.3mol of ammonia. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

0.767 moles of ammonium phosphate are produced

Explanation:

The reaction of ammona (NH3), with phosphoric acid is:

3 NH3 + H3PO4 → (NH4)3PO4

Where 3 moles of ammonia reacts per mole of H3PO4 to produce 1 mole of ammonium phosphate.

If 2.3 moles of ammonia reacts, the moles of ammonium phosphate produced if phosphoric acid is in excess are:

2.3 moles NH3 * (1 mole (NH4)3PO4 / 3 moles NH3) =

0.767 moles of ammonium phosphate are produced

The answer options is d

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.