A 75.0 gram sample of water at 25.0 degrees Celsius is mixed with a 100. Gram sample of water at 60.0 degrees Celsius. What is the final temperature of the water?

The final temperature of the water = 45°C

Explanation:

Heat lost = heat gained

Heat lost by water at 60°C = m₁CΔT₁

Heat gained by water at 25°C = m₂CΔT₂

where m₁ is mass of water at 60°C  = 100.0 g; m₂ is mass of water at 25°C = 75.0 g

C, specific heat capacity of water = 4.18 J/g°C

ΔT₁ = (60 - T); ΔT₂ = (T - 25); T = final temperature of the water

m₁CΔT₁ = m₂CΔT₂

100 * C * (60 - T) = 75 * C * (T - 25)

-100T + 6000 = 75T - 1875

-(100T + 75T) = -(6000 + 1875)

175T = 7875

T = 45°C

Therefore, final temperature of the water = 45°C

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