Determine the number of Au atoms found in 5.18 grams of gold. A.1.02x1022 atoms
B. 3.84 x 1022 atoms
C.2.13 x 1022 atoms
D.4.58x1022 atoms
1.58 x 1022. atoms
Please let me know

1.58× 10²² atoms of Au

Explanation:

Given data:

Mass of gold = 5.18 g

Number of atoms of gold = ?

Solution:

First of all we will calculate the number of moles of gold.

Number of moles = mass/molar mass

Number of moles = 5.18 g/196.96 g/mol

Number of moles = 0.0263 mol

Number of atoms:

Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms of Au

0.0263 mol × 6.022 × 10²³ atoms of Au / 1mol

0.158× 10²³ atoms of Au

1.58× 10²² atoms of Au

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.