How many Joules must be removed to condense 150.0g of steam at 100.0 degrees Celsius to water at 100.0 degrees celcius

339kJ

Explanation:

Given parameters:

Mass of steam  = 150g  = 0.15kg

Initial temperature of steam  = 100°C

Final temperature of water  = 100°C  

Unknown:

Quantity of heat that must be removed to condense the steam = ?

Solution:

The heat involved here is a latent heat because there is no change temperature. The process is just a phase change.

  H  = mL

m is the mass

L is the latent heat of vaporization  = 2,260 kJ/kg

Insert the parameters and solve;

 H = 0.15kg x 2,260 kJ/kg

 H  = 339kJ

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.