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Chemistry, 09.11.2020 21:00 randlemccray1907
A pupil heated 1.24 g of copper carbonate strongly. The chemical reaction which
took place is represented by the equation:
CuCO3(s) → CuO(s) + CO2(g)
He then heated the 0.80 g of solid again. When he weighed it after cooling, its
mass was still 0.80 g. Explain why it had not changed in mass this time.
After the solid which remained had cooled, he weighed it.
He found that its mass was 0.80 g.
(i) Why did the pupil find a decrease in mass in this experiment?
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A pupil heated 1.24 g of copper carbonate strongly. The chemical reaction which
took place is repre...
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