It is easier to determine the electron configurations for the p-block elements in periods 1, 2, and 3 than to determine the electron configurations for the rest of the p-block elements in the periodic table because

they have a larger number of core electrons.

their electrons are assigned to s and p orbitals only.

their electrons are placed in a higher number of orbitals.

they have more valence electrons available for bonding.

Answer is: their electrons are assigned to s and p orbitals only.

1) Nitrogen (N) is an element from period 2, it only have s and p orbitals.

Electron configuration of nitrogen atom: ₇N 1s² 2s² 2p³.

2) Antimony beside s ans p orbitals, also have d orbitals. Antimony is a chemical element with symbol Sb (from Latin: stibium) and atomic number 51, it is in period 5.

Electron configuration of antimony:

₅₁Sb 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹⁰5s²5p³.

Five calence electrons of antimony are in 5s and 5p orbitals.

Answer is: their electrons are assigned to s and p orbitals only.

1) Nitrogen (N) is an element from period 2, it only have s and p orbitals.

Electron configuration of nitrogen atom: ₇N 1s² 2s² 2p³.

2) Antimony beside s ans p orbitals, also have d orbitals. Antimony is a chemical element with symbol Sb (from Latin: stibium) and atomic number 51, it is in period 5.

Electron configuration of antimony:

₅₁Sb 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹⁰5s²5p³.

Five calence electrons of antimony are in 5s and 5p orbitals.

Th correct answer is:

*Their electrons are assigned to s and p orbitals only.

This is because as you move above period 3, as shown by the perodic table, the D block joins the party.

Th correct answer is:

*Their electrons are assigned to s and p orbitals only.

This is because as you move above period 3, as shown by the perodic table, the D block joins the party.