How many moles of carbondioxide are produced when 0.2mol of sodium carbonate react with excess hydrovhloric acid

0.2 moles of CO₂  are produced

Explanation:

Given data:

Moles of CO₂ produced = ?

Moles of Na₂CO₃ react = 0.2 mol

Solution:

Chemical equation:

Na₂CO₃ + 2HCl       →     2NaCl + CO₂ + H₂O

Now we will compare the moles of CO₂ with Na₂CO₃ .

                   Na₂CO₃          :             CO₂

                       1                  :               1

                    0.2                :             0.2

Thus, 0.2 moles of CO₂  are produced.

i think a, hope it .

explanation:

the answer for sodium is 0.186

the answer for rubidium is 0.251