What is the boiling point in °C) of a 0.527 m aqueous solution of LiBr?
Enter your rounded answer with
3 decimal places.

100.54 °C

Explanation:

Supposing complete ionization:
LiBr → Li{+} + Br{-] [two ions]

• (0.527 m LiBr) x (2 mol ions / 1 mol LiBr) = 1.054 m ions

• (0.512 °C/m) x (1.054 m) = 0.540 °C change

• 100.00°C + 0.540 °C = 100.54 °C

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.