sodium hydroxide is extremely soluble in water. a saturated solution contains 678.57 grams of sodium hydroxide 1.00 liter of solution. calculate the molarity of a saturated sodium hydroxide solution.

M = 17 M

Explanation:

Given data:

Mass of sodium hydroxide = 678.57 g

Volume of solution = 1.00 L

Molarity  of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of sodium hydroxide:

Number of moles = mass/molar mass

Number of moles = 678.57 g /40 g/mol

Number of moles = 17 mol

Molarity:

M =  17 mol/1.00 L

M = 17 mol/L

M = 17 M

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :