1. Assume alpha decay occurs on the following isotopes. What atomic mass, atomic number, and atomic symbol will the product have?
a. Silicon-28
i. Mass:
II. Number:
Symbol:

Explanation:

Given parameters:

   Isotope ;

           Si - 28

           ²⁸₁₄Si;

The specie undergoes an alpha decay; An alpha particle resembles a helium atom;

           ²⁸₁₄Si   →  ⁴₂He  +   ?

In nuclear reactions, the mass and atomic numbers are usually conserved;

   So let specie unknown be denote as X

          ᵃₙX;

           ²⁸₁₄Si   →  ⁴₂He  +   ᵃₙX

Sum of the mass number on the reactant side must equal to that on the product side;

         28  = 4 + a

         28 - 4  = a

               a  = 24  mass number of X;

   14  = 2 + n

   n = 14 - 2  = 12   atomic number of X;

 Now, the species X with an atomic number of 12 is magnesium

  Symbol is Mg

   Mass number   = 24

radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold

the nucleus together due to an excess of either protons or neutrons.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.