The temperature of a sample of gas in a steel tank at 0.30 ATM at 25 Celsius if the pressure W20.59 ATM what would be the final temperature inside the tank in kelvin

The final temperature : 313.06 °C

Gay Lussac's Law  

When the volume is not changed, the gas pressure is proportional to its absolute temperature  

P1=0.3 atm

T1=25 + 273=298 K

P2=0.59 atm

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2