Which statement about the quantum mechanical solution for the hydrogen atom is INCORRECT? Group of answer choices

A. The ms quantum number is always a fraction.

B. The principle quantum number, n, can have a value of 1.

C. The ml quantum number must have a positive value.

D. The angular momentum quantum number l = 1 corresponds to the p subshell.

C. The ml quantum number must have a positive value.

Explanation:

The single electron in hydrogen can be found in a ground state orbital of 1s having a magnetic quantum number ml = 0.

Similarly, this one electron can be excited to other higher energy levels such as 2p, 3p, 3d etc

The magnetic quantum numbers ml for higher np sub-levels of the hydrogen atom have magnetic quantum numbers; -1, 0 and 1.

The nd sub-levels have magnetic quantum numbers; -2, -1, 0, 1, 2. We can see from the foregoing that magnetic quantum number ml for hydrogen atom is not always positive.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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