Be sure to answer all parts. Calculate the percent ionization of benzoic acid for the following concentrations: (a) 0.80 M, (b) 0.00080 M.

(a)

(b)

Explanation:

Hello!

In this case, since the ionization of benzoic acid produces benzoate and hydrogen ions:

Whose equilibrium expression is:

Whereas Ka is its acid ionization constant which equals 6.25x10⁻⁵, and each concentration can be expressed in terms of the reaction extent ():

In such a way, for the two given initial concentrations, 0.80 M and 0.00080 M we compute :

(a) 0.80 M

(b) 0.00080 M

Thus, the percent ionization for each case turns out:

(a)

(b)

Best regards.