Use the materials to build prototypes for your two bumpers. Tape a bumper to the box so the ball will hit it properly. Set the box at the foot of the ramp so the bumper is touching the ramp. Then run the test and take measurements using the setup from task 1. Switch bumpers and run the second test. Perform three trials for each test, and record the data in the table. Find the average of the measurements to get a final reading. (For both bumper prototypes, subtract two inches from the average because the bumper changes the starting location of the box by two inches.)

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Sorry i dont understand the question can you rephase it?

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.