Match the options to correct boxes to write the formula for Iron(II) chloride: FeCl2
I need help!!

The correct order are;

1) Multivalent metal cation

2) Charge on multivalent metal cation

3) Non metal anion

4) Charge on anion

5) Number of ions needed to neutralize +ve cation

6) Final Formula

7) FeCl₂

Please find attached the required solution diagram

Explanation:

Iron, Fe, which is a transition metal, form compounds in which it exists as +3 and +2, therefore, it is a multivalent metal

The amount (number) of charge from the anion with a charge of -1, needed to neutralize the +2 charge in the multivalent metal cation is 2

The final compound formed between the anion and the cation is therefore FeCl₂

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :