According to the following reaction, how many grams of sulfur are formed when 37.4 g of water are formed? 2 H2S(g) + SO2(g) → 3 S(s) + 2H2O(l)

Mass = 100.8 g

Explanation:

Given data:

Mass of sulfur form = ?

Mass of water formed = 37.4 g

Solution:

Chemical equation:

2H₂S + SO₂      →      3S + 2H₂O

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 37.4 g/ 18 g/mol

Number of moles = 2.1 mol

Now we will compare the moles of water with sulfur.

                   H₂O        :         S

                      2          :         3

                  2.1           :     3/2×2.1 = 3.15 mol

Mass of sulfur:

Mass = number of moles × molar mass

Mass = 3.15 mol ×  32 g/mol

Mass = 100.8 g

the answer your looking for is c).