Calculate the volume in ml of a 0.555 M NaHCO3 solution that contains 14.7 g of NaHCO3. ml

315 mL

General Formulas and Concepts:

Explanation:

Step 1: Define variables

0.555 M NaHCO₃

14.7 g NaHCO₃

Step 2: Define conversions

Molar Mass of Na - 22.99 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of NaHCO₃ - [22.99 + 1.01 + 12.01 + 3(16.00)] g/mol = 84.01 g/mol

1 L = 1000 mL

Step 3: Find moles of solute

= 0.174979 mol NaHCO₃

Step 4: Find amount of solution

Step 5: Convert

= 315.278 mL

Step 6: Simplify

We are given 3 sig figs.

315.278 mL ≈ 315 mL

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current