Calculate the number of grams of CuSO4 found in 3.29 mL of a 4.00 M CuSO4 solution. grams CuSO4

2.08g

Explanation:

Given parameters:

  Volume of CuSO₄  = 3.29mL

  Molarity  = 4M

Unknown:

Mass of CuSO₄ = ?

Solution:

Let us find the number of moles from the given parameters first;

     Number of moles  = molarity x volume

           1000mL = 1L

Express the volume of the given CuSO₄ in L = 3.29 x 10⁻³L

   Number of moles  = 4 x 3.29 x 10⁻³ = 0.013mol

So;

  Mass of CuSO₄ = number of moles x molar mass

      Molar mass of  CuSO₄  = 63.6 + 32 + 4(16) = 159.6g/mol

 Mass of CuSO₄  = 0.013mol  x 159.6g/mol

 Mass of CuSO₄  = 2.08g

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

the answer is c

tell me if wrong