please answer I will give brainiest to who helps. On the morning of a birthday party, a balloon is filled with 8.5 L of helium (He) when the temperature is 294 kelvin. The party starts at 4:00 p. m., at which time, the temperature has risen to 305 kelvin. What is the new volume of the balloon?

V₂ = 8.8 L

Explanation:

Given data:

Initial volume = 8.5 L

Initial temperature = 294 K

Final temperature = 305 K

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 8.5 L × 305 K / 294 k

V₂ = 2592.5 L.K / 294 K

V₂ = 8.8 L

i think it is true since you can test the answer and can use observations to complete it.