Chemistry, 29.10.2020 16:50 daniiltemkin20
The second-order reaction CH3CHO→CH4+CO has the reaction constant k of 6.73×10−5 L/mol s. If the initial concentration of CH3CHO is 0.551 mol/L, what is the concentration of CH3CHO after 45.0 seconds? Your answer should have 3 significant figures (three decimal places).
Answers: 1
![[CH_3CHO]=0.550M](/tpl/images/0851/4391/b9453.png)
![r=\frac{d[CH_3CHO]}{dt} =-k[CH_3CHO]^2](/tpl/images/0851/4391/4a741.png)
![\frac{1}{[CH_3CHO]} =kt+\frac{1}{[CH_3CHO]_0}](/tpl/images/0851/4391/ddc80.png)
![\frac{1}{[CH_3CHO]} =6.73x10^{-5}\frac{L}{mol*s}*45.0s +\frac{1}{0.551mol/L}\\\\\frac{1}{[CH_3CHO]}=3.03x10^{-3}L/mol+1.81L/mol](/tpl/images/0851/4391/201eb.png)
![\frac{1}{[CH_3CHO]} =1.82L/mol](/tpl/images/0851/4391/b186d.png)
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The second-order reaction CH3CHO→CH4+CO has the reaction constant k of 6.73×10−5 L/mol s. If the ini...
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