The second-order reaction CH3CHO→CH4+CO has the reaction constant k of 6.73×10−5 L/mol s. If the initial concentration of CH3CHO is 0.551 mol/L, what is the concentration of CH3CHO after 45.0 seconds? Your answer should have 3 significant figures (three decimal places).

Explanation:

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In this case, since the rate law for this chemical reaction would be:

The integrated rate law after its demonstration is:

Thus, for the given rate constant, initial concentration of CH3CHO and elapsed time, the resulting concentration is:

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