When 1.34 g Zn(s) reacts with 60.0 mL of 0.750 M HCl(aq), 3.14 kJ of heat are produced. Determine the enthalpy change per mole of zinc reacting for the reaction:

Explanation:

Zn    +     2HCl   =   ZnCl₂  +     H₂

1 mole   2 mole  

1.34 g = 1.34 / 65. = .0206 mole

60 mL of .75 M HCl = .045 mole of HCl

so full .0206 mole of Zn will react with .0412 mole of HCl

.0206 mole of Zn gives out 3.14 kJ of heat

1 mole of Zn will react to give  152.43 kJ of heat

enthalpy change of heat per mole of Zn

= 152.43 kJ .

explanation:

two years ago, when picking flowers in the mountains back of yosemite valley, i found a book. it was blotted and storm-beaten; all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however; many of the inner pages were well preserved. and although all were more or less stained and torn, whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today; its granite pages have been torn and blurred by the same storms that wasted the castaway book.

two years ago, when picking flowers in the mountains back of yosemite valley; i found a book. it was blotted and storm-beaten, all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however, many of the inner pages were well preserved. and although all were more or less stained and torn; whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today, its granite pages have been torn and blurred by the same storms that wasted the castaway book.

yes the answer is total mass in unchanged   : )