What volume in mL of 0.300 M NaF would be required to make a 0.0715 M solution of NaF when diluted to 250.0 mL with water

The volume of 0.300 M NaF required is 59.6 ml

Explanation:

According to the dilution law,

where,

= concentration of concentrated NaF solution = 0.300 M

= volume of pure concentrated Na F solution = ?

= concentration of diluted NaF solution= 0.0715 M

= volume of diluted NaF solution= 250.0 ml

Thus the volume of 0.300 M NaF required is 59.6 ml

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c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.