A 3.458 g sample of KHP, a monoprotic acid, requires 45.71 mL of a KOH solution to reach the endpoint. What is the concentration of the KOH solution

0.3704M is the concentration of KOH

Explanation:

The reaction of the monoprotic acid, KHP, with KOH is:

KHP + KOH → H₂O + K₂P

An acid reacts with a base to produce water and a salt

The molar mass of KHP is 204.22g/mol, that means in 3.458g of KHP you have:

3.458g * (1mol / 204.22g) = 0.01693 moles KHP.

At the endpoint:

Moles KHP = Moles KOH. That means moles KOH Are 0.01693 moles. These moles are in 45.71mL = 0.04571L, the molar concentration is:

0.01693 moles KOH / 0.04571L =

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

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it should be all of them because it asks if you included all of those in your answer

explanation: