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Chemistry, 29.10.2020 04:00 scm9170

A 160.0-mL solution contains 2.15 g of sodium benzoate and 2.79 g of benzoic acid. Calculate the pH of the solution. For benzoic acid, Ka=6.5×10−5. Express your answer using two decimal places.

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A 160.0-mL solution contains 2.15 g of sodium benzoate and 2.79 g of benzoic acid. Calculate the pH...

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