How much work (in J) is required to expand the volume of a pump from 0.0 L to 2.2 L against an external pressure of 1.2 atm

267.498 J is required to expand the volume of a pump from 0.0 L to 2.2 L against an external pressure of 1.2 atm

Explanation:

The volume change work of a gas is the work necessary for the gas to go from an initial volume Vi to a final volume Vf. If the volume decreases, the gas will have been compressed and it is a compression work; whereas if the volume increases, the gas will have expanded and it is expansion work.

The work is calculated by:

W= - P*ΔV= -P*(Vfinal - Vinitial)

In this case:

Replacing:

W= -121590 *0.0022 m³= - 267.498 N*m= -267.498 J

267.498 J is required to expand the volume of a pump from 0.0 L to 2.2 L against an external pressure of 1.2 atm

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.