1. Consider the following: HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (liq) ∆H = -57.62 kJ/mol If a 25.0 mL of 0.144 M HCl (aq) at 25oC is added to 20.0 mL of 0.132 M NaOH (aq) at 25oC, calculate the final temperature of the contents. Assume the volumes are additive and that the resulting salt water solution has a density of 1.04 g/mL with a specific heat capacity of 3.93 J/goC. Note that you will also need to determine the limiting reactant.

25.82°C

Explanation:

Based on the reaction, 1 mole of HCl and 1 mole of NaOH reacts, that means the reaction is 1:1. The moles of each compound are:

Moles HCl:

0.025L * (0.144mol/L) = 0.0036 moles HCl

Moles NaOH:

0.020L * (0.132mol/L) = 0.00264 moles NaOH

Thus, moles of reaction are 0.00264 moles

The heat released in a calorimeter is obtained using the equation:

Q = m*c*ΔT

Where Q is heat released in the reaction:

0.00264 moles * (-57.62kJ/mol) = 0.1521kJ = 152.1J of reaction

m is mass of the solution:

25.0mL + 20.0mL = 45mL * (1.04g/mL) = 46.8g

c is specific heat of the solution:

3.93J/gºC

And ΔT is change in temperature.

Solving for ΔT:

Q /mc = ΔT

151.2J / 46.8g*3.93J°C = 0.82°C = ΔT = Final temperature - Initial temperature.

Final temperature = 0.82°C + 25°C =

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: