What is the temperature, in degrees Celsius, of a 10.5 grams sample of Neon gas confined to a volume of 2.50 L at a pressure of 1.00 atm.

–215 °C

Explanation:

From the question given above, the following data were obtained:

Mass of Ne = 10.5 g

Volume (V) = 2.50 L

Pressure (P) = 1 atm

Temperature (T) =?

Next, we shall determine the number of mole present in 10.5 gof Neon, Ne. This can be obtained as follow:

Mass of Ne = 10.5 g

Molar mass of Ne = 20 g/mol

Mole of Ne =.?

Mole = mass /Molar mass

Mole of Ne = 10.5 / 20

Mole of Ne = 0.525 mole

Next, we shall determine the temperature of the sample of Neon, Ne. This can be obtained as follow:

Volume (V) = 2.50 L

Pressure (P) = 1 atm

Number of mole (n) = 0.525 mole

Gas constant (R) = 0.0821 atm.L/Kmol

Temperature (T) =?

PV = nRT

1 × 2.5 = 0.525 × 0.0821 × T

2.5 = 0.525 × 0.0821 × T

Divide both side by 0.525 × 0.0821

T = 2.5 / (0.525 × 0.0821)

T = 58 K

Finally, we shall convert 58 K to degree celsius (°C). This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 58 K

T(°C) = 58 – 273

T(°C) = –215 °C

Thus, the temperature of the sample of Neon gas is –215 °C.

i would say b

explanation:

but i think i would need more information than that