What type of bond is this combination most likely to form?

Sodium is a group 1 element with atomic number 1. It has 11 electrons. It is soft reactive metal. It has 1 valence electron.

Fluorine is a group 7 element, a hologen with 7 valence electron. It is a most reactive non metal.

When sodium react with fluorine, ionic bond is formed in the resulting compound sodium fluoride.

One sodium and fluorine each totaling 2 atoms are enough to make the bond.

As the bond is formed, both atoms have octet structure. That is they each have 8 electrons on their outermost shells.

The positive charge on sodium indicates that sodium had lost 1 electron to fluorine atom.

The negative charge on fluorine ion indicates that fluorine atom had gained 1 electron from sodium atom to form negative ion.

The name of the compound is sodium fluoride with formula NaF.

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considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.