Calculate the volume in liters occupied by 39.6 grams of NO at 5.54 atm and 72°C

6.75 L

Explanation:

The following data were obtained from the question:

Mass of NO = 39.6 g

Pressure (P) = 5.54 atm

Temperature (T) = 72°C

Volume (V) =...?

Next, we shall determine the number of mole in 39.6 g of NO. This is illustrated below:

Mass of NO = 39.6 g

Molar mass of NO = 14 + 16 = 30 g/mol

Mole of NO =..?

Mole = mass /Molar mass

Mole of NO = 39.6 /30

Mole of NO = 1.32 moles

Next, we shall convert 72°C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 72°C

Temperature (T) = 72°C + 273

Temperature (T) = 345 K

Finally, we shall determine the Volume occupied by NO as follow:

Pressure (P) = 5.54 atm

Temperature (T) = 345 K

Number of mole (n) = 1.32 moles

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =...?

PV =nRT

5.54 × V = 1.32 × 0.0821 × 345

5.54 × V = 37.38834

Divide both side by 5.54

V = 37.38834 / 5.54

V = 6.75 L

Therefore, the volume occupied by 39.6 g of NO is 6.75 L

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