Janelle needs to make 150.0 mL of a 0.250 M HCl solution. How much concentrated HCl (12.0 M) will she need

3.125 mL

Explanation:

The following data were obtained from the question:

Molarity of stock solution (M1) = 12 M

Molarity of diluted solution (M2) = 0.250 M

Volume of diluted solution (V2) = 150 mL

Volume of stock solution needed (V1) =.?

The volume of stock solution needed can be obtained by using the dilution formula as shown below:

M1V1 = M2V2

12 × V1 = 0.250 × 150

12 × V1 = 37.5

Divide both side by 12

V2 = 37.5/12

V2 = 3.125 mL

Therefore, the volume of the stock solution needed is 3.125 mL

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