Chemistry, 26.10.2020 17:40 mirandapaige246

Complete the balanced dissociation equation for the compound below in aqueous solution. If the compound does not dissociate, write NR after the reaction arrow. NaBr(s)

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Answer from: jcece9055

The balanced dissociation equation for the compound, NaBr is:

NaBr(s) —> Na⁺(aq) + Br¯(aq)

A dissociation equation is an equation showing the ions that makes up a compound.

NOTE:

Dissociation will only occurs when the compound is dissolved in water

The dissociation equation for NaBr can be written as follow:

NaBr(s) —> Na⁺(aq) + Br¯(aq)

From the equation above, we can see that the ions that makes up NaBr are clearly seen. Hence, the above equation is the dissociation equation for NaBr.

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Answer from: gtsaeg7277

NaBr(s) → Na+ (aq) + Br– (aq)

Explanation:

Dissociation refers to the separation of an ionic compound or molecule into its constituent ions when dissolved in water. The ions with their respective charges make up the ionic compound, hence, an ionic compound is said to dissociate when the respective cations (+ charge) and anions (- charge) are released in an aqeous solution.

In this case, NaBr(s) or Sodium bromide is an ionic solid {signified by the (s) sign}. Upon dissolving in water, NaBr(s) breaks down into the ionic charges that makes it up i.e dissociates. The balanced ionic equation is as follows:

NaBr(s) → Na+ (aq) + Br– (aq)

Note: 1 mole of the solid ionic compound dissociates into one sodium ion (Na+) and one bromide ion (Br–).

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

answer: enthalpy

explanation:

for a exothermic reaction, the energy is released i.e. the energy of the products is lower than the energy of the reactants.

$\delta h=e_p-e_r$

$\delta h$ = enthaply

$e_p$ = energy of products

$e_r$ = energy of reactants

as $e_p< e_r$ , thus $\delta h$ comes out to be negative. negative value of enthalpy shows that the reaction is exothermic.

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Complete the balanced dissociation equation for the compound below in aqueous solution. If the compo...