Calcium hydroxide is slightly soluble in water. About 1 gram will dissolve in 1 liter. What are the spectator ions in the reaction of such a dilute solution of calcium hydroxide with hydrochloric acid

2H+(aq) + 2OH-(aq) ---> 2H2O(l)

Cl-(aq) , Ca2+(aq) are the spectator ions.

Explanation:

In order to make the ionic equation we need to separate the components which are stable substances from the aqueous components.

Molecular equation:

2HCl (aq) + Ca(OH)2(aq) ---> CaCl2 (aq) + 2H2O(l)

ionic equation:

2H+(aq) + 2Cl-(aq) + Ca2+(aq) + 2OH-(aq) ---> Ca2+(aq) + 2Cl- (aq) + 2H2O(l)

In order to make the final equation, it has to be canceled all the species which are present in moth sites of the equation. So, Cl-(aq) , Ca2+(aq) are the spectator ions.

final equation: 2H+(aq) + 2OH-(aq) ---> 2H2O(l)

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"