Provide the coefficients needed to balance the redox reaction given. Choose... Fe(s) + Choose... Cl2(g)→ Choose... Fe3+(aq) + Choose... Cl-(aq)

3 Cl₂(g) + 2 Fe(s) → 6 Cl⁻(aq) + 2 Fe³⁺(aq)

Explanation:

Step 1: Write the unbalanced redox reaction

Fe(s) +  Cl₂(g) → Fe³⁺(aq) + Cl⁻(aq)

Step 2: Identify both half-reactions

Reduction: Cl₂(g) → Cl⁻(aq)

Oxidation: Fe(s) → Fe³⁺(aq)

Step 3: Perform the mass balance

Cl₂(g) → 2 Cl⁻(aq)

Fe(s) → Fe³⁺(aq)

Step 4: Perform the charge balance

2 e⁻ + Cl₂(g) → 2 Cl⁻(aq)

Fe(s) → Fe³⁺(aq) + 3 e⁻

Step 5: Multiply both half-reactions by numbers that make that the number of electrons gained and lost are equal

3 × [2 e⁻ + Cl₂(g) → 2 Cl⁻(aq)]

2 × [Fe(s) → Fe³⁺(aq) + 3 e⁻]

Step 6: Add both half-reactions and cancel what is repeated in both sides

6 e⁻ + 3 Cl₂(g) + 2 Fe(s) → 6 Cl⁻(aq) + 2 Fe³⁺(aq) + 6 e⁻

3 Cl₂(g) + 2 Fe(s) → 6 Cl⁻(aq) + 2 Fe³⁺(aq)

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates