"How many grams of water can be produced when 20.0 mL of 0.600 M H2SO4 react with 40.0 mL of 0.800 M NaOH"

0.432 g

Explanation:

Equation of the reaction;

H2SO4(aq) + 2NaOH > Na2SO4(aq) + 2H2O(l)

Amount of H2SO4= concentration × volume = 20.0/1000 × 0.600 M= 0.012moles

If 1 mole of H2SO4 yields 2 moles of

water

0.012 moles of H2SO4 yields 0.012 × 2/1 = 0.024 moles

For NaOH

Amount= 40/1000 × 0.8 = 0.032 moles

If 2 moles of NaOH yields 2 moles water

0.032 moles of NaOH also yields 0.032 moles of water

Hence H2SO4 is the limiting reactant

Thus;

Mass of water = 0.024 moles × 18g/mol = 0.432 g

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.