Answers: 1
![[BH^+] = \dfrac{1.00 \ g}{110.54 \ gmol \times 0.100 L}](/tpl/images/0840/1969/7f9ae.png)
![[BH^+]=](/tpl/images/0840/1969/69ccf.png)
0.0905 M![[B] = \dfrac{x \ g}{74.083 \ gmol \times 0.100 L}](/tpl/images/0840/1969/63615.png)
![\dfrac{[B]}{[BH^+]}=\dfrac{0.135x \ M}{0.0905 \ M }}](/tpl/images/0840/1969/324e7.png)
![\dfrac{[B]}{[BH^+]}=1.49x](/tpl/images/0840/1969/229bc.png)
![log _{10}\dfrac{[B]}{[BH^+]}=log _{10}1.49x](/tpl/images/0840/1969/517c5.png)
![pH = pK_a + log _{10} \dfrac{[B]}{[BH^+]}](/tpl/images/0840/1969/cf34c.png)
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