Describe a procedure to separate a mixture of sugar, black pepper, and pebbles.

Answer : The procedure to separate the mixture of sugar, black pepper and pebbles would require physical methods.

First step is to pass the mixture through a grid that traps the pebbles in it and allows the passage of black pepper and sugar from it or alternatively, physically hand-picking up the pebbles can also be done.

Next step is to add water to the mixture to the sugar and black pepper, stir this solution until all the sugar dissolves in the water. Then pass this solution from a filter paper and collect the filtrate in a beaker.

The residue would contain the black pepper on it, it can be dried after separation.

To obtain the sugar which is dissolved in water, one can evaporate the water in it and get the sugar at the bottom of the beaker.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."