g An aqueous solution of 2.35 M urea is made. The density of the solution is 1.029 g/mL. What is the molality (molal concentration) of urea in the solution. (Molar mass of urea

1.06 m

Explanation:

We have 2.35 moles of pure urea in 1000 ml solution

Mass of the solution = 1000 × 2.35 = 2350 g

Mass of pure urea = 2.35 ×60 = 141 g

Mass of water= 2350 - 141 = 2209 g

Molality = 2.35 / 2209 × 1000 =1.06 m

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