A gas occupies a volume of 500 milliliter sat pressure of 38.0 kPa and a temperature of 298K. At what temperature will the gas occupy a volume of 250 milliners and have a pressure of 76.0 kPa

T₂ = 298 K

Explanation:

Given data:

Initial volume = 500 mL

Initial pressure = 38.0 KPa

Initial temperature = 298 K

Final temperature= ?

Final pressure = 76.0 KPa

Final volume = 250 mL

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

T₂  = = P₂V₂T₁ / P₁V₁

T₂ = 76.0 KPa × 250mL × 298 K / 38.0 KPa × 500 mL  

T₂ = 5662000 KPa.mL. K /19000 KPa. mL

T₂ = 298 K

chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances. these processes are called chemical reactions and, in general, are not reversible except by further chemical reactions. some reactions produce heat and are called exothermic reactions and others may require heat to enable the reaction to occur, which are called endothermic reactions. understanding chemical changes is a major part of the science of chemistry.