Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 10.1 g of methane is mixed with 58. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to significant digits.

Explanation:

CH₄ + 2O₂ = CO₂ + 2H₂O

1 mole + 2 moles  = 1 moles + 2 moles

10.1 gm of methane = 10.1 / 16 = .63 moles of methane

58 g of oxygen = 58 / 32 = 1.8125 moles of oxygen

1 moles of methane reacts with 2 moles of oxygen to make 1 mole of CO₂

.63 moles of methane reacts with 1.26 moles of oxygen to make .63 mole of

CO₂

so CO₂ formed = .63 moles

.63 x 44 = 27.7 grams of CO₂

answer; i believe that the correct answer is (c) explore the outer planets; / plz check good luck

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation: