A chemist dissolves 320.mg of pure nitric acid in enough water to make up 290.mL of solution. Calculate the pH of the solution. Be sure your answer has the correct number of significant digits.

1.7

Explanation:

The formula to be used here is;

pH = -log[H⁺]

To determine the concentration of H⁺ of the nitric acid (HNO₃), formula for molarity is used

Molarity = number of  moles/volume (in dm³ or L)

number of moles (n) = given mass/molar mass

Molar mass of HNO₃ = 1 + 14 + (16 x 3)

= 63g

given mass (in grams) = 320mg⇔0.32g (where 1000mg = 1g)

Thus; n = 0.32/63

n = 0.0051 moles

Volume of acid = 290 mL ⇔ 0.29 L (where 1000 mL = 1L)

Molarity = n/volume;

0.0051/0.29

Molarity = 0.018M

pH = -log 0.018

pH = 1.7

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

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