g If 0.600 g of a gas occupies 211 mL at 24 oC and 660 mmHg of pressure, what is the molar mass of the gas

79.89 g/mol

Explanation:

The following data were obtained from the question:

Mass (m) of gas = 0.6 g

Volume (V) = 211 mL

Temperature (T) = 24 °C

Pressure (P) = 660 mmHg

Molar mass of gas =.?

Next, we convert 24 °C to Kelvin temperature. This can be obtained as follow:

Temperature (K) = temperature (°C) + 273

Temperature (°C ) = 24 °C

Temperature (K) = 24 + 273 = 297 K

Next, we shall convert 211 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

211 mL = 211 mL × 1 L / 1000 mL

211 mL = 0.211 L

Next, we shall convert 660 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

660 mmHg = 660 mmHg × 1 atm / 760 mmHg

660 mmHg = 0.868 atm

Next, we shall determine the number of mole of the gas. This can be obtained as shown below:

Volume (V) = 0.211 L

Temperature (T) = 297 K

Pressure (P) = 0.868 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

PV = nRT

0.868 × 0.211 = n × 0.0821 × 297

Divide both side by 0.0821 × 297

n = (0.868 × 0.211) / (0.0821 × 297)

n = 7.51×10¯³ mole.

Finally, we shall determine the molar mass of the gas as shown below:

Mass of gas = 0.6 g

Number of mole of gas = 7.51×10¯³ mole.

Molar mass of gas =.?

Mole = mass /Molar mass

7.51×10¯³ = 0.6 / Molar mass

Cross multiply

7.51×10¯³ × molar mass = 0.6

Divide both side by 7.51×10¯³

Molar mass = 0.6 / 7.51×10¯³

Molar mass of gas = 79.89 g/mol