Which two of the four quantum numbers determine the energy level of an orbital in a multielectron atom? Which two of the four quantum numbers determine the energy level of an orbital in a multielectron atom? nn and ll nn and mlml ll and mlml

The correct answer is - n and l.

Explanation:

The size of an orbital is determined by the principal number of shell which is represented by n. The larger the energy level (n) bigger the size of the orbital. N can be any integer value: 1, 2, 3 . . . . and so on.

l represents the angular momentum or subshell number provides the overall shape of an orbital in this subshell only integer values between 0 and n-1 are permitted.

Thus, n & l are two quantum numbers that determine the energy level of an orbital in a multielectron atom.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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