Question 5 1 pts

Chloroethene, C2H3C1, reacts with oxygen according to the equation below.

2 C2H2Cl (9) + 5O2(g) + 4CO2 (g) + 2 H20 g) + 2 HCl (9)

What is the amount, in mol, of H2O produced when 10.0 mol of C2H3Cl and 10.0 mol of

O2 are mixed together, and the above reaction goes to completion?

08.00

10.0

04.00

20.0

Lo

4.00 moles of water

Explanation:

The equation of the reaction is:

2 C2H2Cl (9) + 5O2(g) > 4CO2 (g) + 2 H20( g) + 2 HCl(g)

To find the limiting reactant,  we find the species that yields the lowest number of moles of water.

From the reaction equation;

2 moles of C2H2Cl  yields 2 moles of water

10 moles of C2H2Cl  yields 10 * 2/2 = 10 moles of water

Similarly;

5 moles of oxygen yields 2 moles of water

10 moles of oxygen will yield 10 *2/5 =4 moles of water

Hence oxygen is the limiting reactant.

10 moles of oxygen yields 4 moles of water.