How do you calculate the energy, in joules, of a photon of ultraviolet light with a frequency of 6.8 x 10^15 Hz?

Energy is the quantitative unit, which is measured in joules. The energy of a photon of UV light having the frequency  6.8×10¹⁵ Hz is 45.08×10⁻¹⁹ Joules.

Given:

Frequency of photon = 6.8×10¹⁵ Hz

Energy of a photon in joule =?

Usingt the formula of energy:

E = h x v

where,

v = frequency

h = planck's constant (6.63×10⁻³⁴Js)

E = energy

Substituting the values in the equation, we get:

E = 6.63×10⁻³⁴Js ×6.8×10¹⁵ Hz

E = 6.63×10⁻³⁴Js ×6.8×10¹⁵ s⁻¹

E = 45.08×10⁻¹⁹ Joules

Therefore, the energy of a photon in the UV region is 45.08×10⁻¹⁹ Joules

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E = 45.08×10⁻¹⁹j

Explanation:

Given data:

Energy of photon  in joule = ?

Frequency of photon = 6.8×10¹⁵ Hz

Solution:

Formula:

E = h.f

f = frequency

h = planck's constant (6.63×10⁻³⁴Js)

E = energy

Value of planck's constant is 6.63×10⁻³⁴Js.

E = 6.63×10⁻³⁴Js ×6.8×10¹⁵  Hz

Hz = s⁻¹

E = 6.63×10⁻³⁴Js ×6.8×10¹⁵  s⁻¹

E = 45.08×10⁻¹⁹j

definition

                    entropy is a measure of the randomness or the extent of disorder of a chemical process.

                      enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

                        entropy is measured in joule per kelvin (jk⁻¹)   whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

                            entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

                              in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.

the answer is barium and copper bromide