How many grams of mgcl2 must be provided 1.89 mole of chloride ions

Mass = 89.97 g

Explanation:

Given data:

Number of moles of chloride ions = 1.98 mol

Mass in grams of MgCl₂ present = ?

Solution:

we can see that 1 mole of MgCl₂ contain 2 moles of chloride ions. Thus 1.89 moles of chloride ions contain moles of MgCl₂ are,

                  Cl₂          :        MgCl₂

                   2            :          1

                  1.89        :        1/2×1.89 = 0.945

Thus, 1.89 moles of chloride ions are provided by 0.945 moles of MgCl₂.

Mass of MgCl₂:

Mass = number of moles × molar mass

Mass = 0.945 mol × 95.211 g/mol

Mass = 89.97 g

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