Give the spectator ions for the reaction that occurs when aqueous solutions of H2SO4 and KOH are mixed. a. OH- and K+
b. H+ and SO4-2
c. K+ and SO4-2
d. H+ and OH-
e. No spectator ions are present.

Option C. K⁺(aq) and SO₄²¯(aq)

Explanation:

We'll begin by writing the ionic equation between H₂SO₄ and KOH.

This is illustrated below:

In solution, H₂SO₄ and KOH will dissociate as follow

H₂SO₄ (aq) —> 2H⁺ (aq) + SO₄²¯ (aq)

KOH (aq) —> K⁺ (aq) + OH¯ (aq)

Thus, aqueous H₂SO₄ and KOH will react as follow:

H₂SO₄ (aq) + 2KOH (aq) —> K₂SO₄ (aq) + 2H₂O (l)

Ionically:

2H⁺(aq) + SO₄²¯(aq) + 2K⁺(aq) + 2OH¯(aq) —> 2K⁺(aq) + SO₄²¯(aq) + 2H₂O (l)

The spectator ions are those ions that appear on both sides of the equation.

From the above ionic equation, the spectator ions are:

K⁺(aq) and SO₄²¯(aq)

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.