1. Calculate the number of grams of solute required for the preparation of 1.5L of 0.32M NaHCO3 (MW=84) V1 X C1 = V2 X C2

40.32 grams of solute required for the preparation of 1.5L of 0.32M NaHCO₃

Explanation:

Molar concentration or molarity is a measure of the concentration of a solute in a solution. Molarity is defined as the number of moles of solute present in one liter of solution.

Molarity is calculated by the expression:

Molarity is expressed in units .

In this case:

Replacing:

Solving:

number of moles of solute= 0.32 M* 1.5 L

number of moles of solute= 0.48 moles

Being the molar weight of NaHCO₃ equal to 84 g / mole, the following rule of three can be applied: if there are 84 grams in 1 mole, how much mass is there in 0.48 moles?

mass= 40.32 grams

40.32 grams of solute required for the preparation of 1.5L of 0.32M NaHCO₃

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.