Calculate the hydronium ion, H3O+ , and hydroxide ion, OH− , concentrations for a 0.0440 M HCl solution. [H3O+]= M [OH−]=

[H3O+] = 0.0440M

[OH-] = 2.27x10⁻¹³M

Explanation:

Based on the equilibrium of water:

2H2O ⇄ H3O+ + OH-

K = 1x10⁻¹⁴ = [H3O+] [OH-] (1)

We can determine [OH-] with [H3O+] or vice versa

As HCl is a strong acid, [HCl] = [H3O+]

That means:

[H3O+] = 0.0440M

And [OH-] is:

1x10⁻¹⁴ / [H3O+] = [OH-]

2.27x10⁻¹³M = [OH-]

thats a little if u want the answer just look it up on google thats what i do haha : )