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A solution of ethanedioic acid was prepared by dissolving 1.01 g of the acid in
water and ma...
Chemistry, 20.10.2020 02:01 ramanpreet
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A solution of ethanedioic acid was prepared by dissolving 1.01 g of the acid in
water and making the volume up to 250 cm in a volumetric flask. A 25.0 cm
sample of this solution was titrated against NaOH and required 18.40 cm NaOH
for neutralisation.
(COOH)2 + 2NaOH —— (COONa)2 + 2H2O
Calculate the number of moles of ethanedioic acid in 1.01 g.
a
Answers: 2
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